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Find the de Broglie wavelength (in nm) of neutrons in

equilibrium at the temperatures 6.00 K and 0.0200 K.

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Final answer:

The de Broglie wavelength of neutrons in equilibrium at temperatures 6.00 K and 0.0200 K can be calculated using the formula λ = h / p, where λ is the de Broglie wavelength, h is Planck's constant, and p is the momentum of the particle.

Step-by-step explanation:

The de Broglie wavelength of a particle can be calculated using the formula: λ = h / p
where λ is the de Broglie wavelength, h is Planck's constant, and p is the momentum of the particle.

For a neutron in equilibrium at a temperature of 6.00 K, we can assume it to be nonrelativistic, and its kinetic energy can be neglected. Therefore, the momentum can be approximated as: p = sqrt(2 × m × (k × T))

where m is the mass of the neutron, k is Boltzmann's constant, and T is the temperature in Kelvin.

Using the given values, we can calculate the de Broglie wavelength: For 6.00 K: λ = h / p

For 0.0200 K: λ = h / p

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