62.7k views
3 votes
Solve the following problems: Show your work! 1. After collecting and planting the seeds from an unknown breeding event in your Fast Plants, you notice 75% of the F1 offspring have purple stems, and 25% have green stems.

What were the most probable genotypes and phenotypes of the parent? F1 Phenotypes ratios: Punnett Square: Parents' Genotypes: Parents' Phenotypes: 2. Hemophilia can be cause by a gene on the X chromosome. The normal allele is dominant to the recessive allele.

A man with normal blood clotting marries a women who is heterozygous for the hemophilia allele. What iss the chance they will have a girl with hemophilia? Parents' genotypes: Parents' phenotypes: Possible Gametes: Punnett Square: Chance that they will have a girl with hemophilia:

User David Rojo
by
7.9k points

1 Answer

4 votes

Final answer:

In the first problem, the most probable genotypes of the parents would be Pp and pp, with corresponding phenotypes of purple stems and green stems. In the second problem, there is a 50% chance that the couple will have a daughter with hemophilia and a 50% chance they will have a daughter without hemophilia.

Step-by-step explanation:

In the first problem, we have 75% of the offspring with purple stems and 25% with green stems. Since purple is dominant, we can determine the genotypes of the parents. Let's represent the purple allele as P and the green allele as p. The most probable genotypes for the parents would be Pp (heterozygous) and pp (homozygous recessive). The corresponding phenotypes would be purple stems and green stems, respectively. In the second problem, the chances of having a girl with hemophilia can be determined using a Punnett square. The man with normal blood clotting is XY, and the woman who is heterozygous for hemophilia is XhX. In this case, there is a 50% chance that they will have a daughter with hemophilia (XhX) and a 50% chance they will have a daughter without hemophilia (XX).

User Aaron Jordan
by
7.6k points