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How much heat in joules is required to raise the temperature of 0.18kg of water from 17c to 60c

User Lllllll
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Final answer:

The specific heat of water is 4.184 J/g °C. You can use the equation Q = mcΔT to calculate the amount of heat required to raise the temperature of a substance. In this case, you need to convert the mass of water to grams and then perform the calculation to find the heat energy in joules.

Step-by-step explanation:

The specific heat of water is 4.184 J/g °C. To calculate the amount of heat required to raise the temperature of a substance, you can use the equation Q = mcΔT, where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

In this case, the mass of water is 0.18 kg, the specific heat capacity of water is 4.184 J/g °C, and the change in temperature is from 17°C to 60°C. First, convert the mass of water to grams: 0.18 kg * 1000 g/kg = 180 g. Then, calculate the heat energy using the formula: Q = mcΔT = (180 g) * (4.184 J/g °C) * (60°C - 17°C).

Perform the calculation to find the heat energy in joules.

User Hallie Swan
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