Final answer:
The object's change in position is calculated using the displacement formula s = ut + (1/2)at², resulting in a total displacement of 350 meters over the 10-second interval as it accelerates.
Step-by-step explanation:
To find out the change in position for an object launched horizontally at an initial speed of 10 meters per second and accelerating for 10 seconds at 5 meters per second squared, we use the formula for displacement under constant acceleration: s = ut + (1/2)at², where 's' is displacement, 'u' is initial velocity, 'a' is acceleration, and 't' is time.
In this case, initial velocity (u) is 10 m/s, acceleration (a) is 5 m/s², and time (t) is 10 seconds.
Substituting the given values into the equation, we get:
s = (10 m/s)(10 s) + (1/2)(5 m/s²)(10 s)²
s = 100 m + 0.5(5)(100)
s = 100 m + 250 m
s = 350 meters.
Therefore, the object has changed its position by 350 meters before reaching the target.