Question

An electron with an initial speed of 540,000 m/s is brought to rest by an electric field. What was the potential difference that stopped the electron?

Answer 1

The potential difference that stopped the electron is approximately -147.6336 volts

Step-by-step explanation:

To find the potential difference (V) that stopped the electron, we can use the equation:

V = (1/2)mv^2/q

Where V is the potential difference, m is the mass of the electron, v is the initial speed of the electron, and q is the charge of the electron.

Plugging in the given values:

V = (1/2)(9.11 × 10^-31 kg)(540,000 m/s)^2/(-1.60 × 10^-19 C)

Simplifying:

V = -147.6336 V

So, the potential difference that stopped the electron is approximately -147.6336 volts.