Final answer:
To melt 200g of ice at 0°C, we need 67,200 J or 67.2 kJ of energy, by multiplying the mass of the ice in kg by the specific heat of fusion (336 J/g) after converting it to the same units.
Step-by-step explanation:
To calculate how much energy is needed to melt 200g of ice at 0°C with the given specific heat of fusion, which is 336 J/g, we can use the equation Q = mLf, where Q is the heat transfer, m is the mass of the ice, and Lf is the latent heat of fusion. First, we convert 200g to kilograms by dividing by 1000, getting 0.2 kg. We then multiply the mass by the latent heat of fusion: Q = 0.2 kg × 336,000 J/kg = 67,200 J, or 67.2 kJ. Since the specific heat of fusion is usually given in kJ/kg, one should ensure proper unit conversion before calculation.