Question

A• Pool A has 900 gallons of water and is leaking 5 gal per minute.

b• Pool B has 750 gallons of water and is leaking 2 gal per minute.
Let m represent the number of minutes the pools are leaking.
How many minutes, m, will it take for the two pools to have the same amount of water?

Answer 1

It will take 50 minutes for Pools A and B to have the same amount of water, after setting up the equation (900 - 5m = 750 - 2m) and solving for m.

Step-by-step explanation:

To find after how many minutes, m, pools A and B will have the same amount of water, we can set up an equation where the amount of water leaking from Pool A equals the amount of water leaking from Pool B. Initially, Pool A has 900 gallons and Pool B has 750 gallons. Pool A leaks at a rate of 5 gallons per minute and Pool B leaks at 2 gallons per minute.

Let's set up our equations:

• Water remaining in Pool A after m minutes: 900 - 5m
• Water remaining in Pool B after m minutes: 750 - 2m

Setting the two expressions equal to each other because we want the volumes to be equal gives us:

900 - 5m = 750 - 2m

Now we'll solve for m:

900 - 5m = 750 - 2m
5m - 2m = 900 - 750

3m = 150
m = 150 / 3

m = 50

So, it will take 50 minutes for the two pools to have the same amount of water.