Question

Write the equation of a line with the slope−53 and point (-3, 3)

y=−2x−43
y=−43x−2
y=−53x−2
y=2x−43

Answer 1

The equation of the line is 5x + 3y = -6.

Step-by-step explanation:

The equation of a line with a given slope and a point can be found using the point-slope form of a linear equation. The point-slope formula is given as y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope.

In this case, the given slope is -5/3 and the point is (-3, 3). Plugging these values into the formula, we get: y - 3 = (-5/3)(x - (-3)).

Simplifying this equation, we have y - 3 = (-5/3)(x + 3). To obtain the equation in standard form, we can multiply through by 3 to eliminate the fraction and rearrange the terms, resulting in 3y - 9 = -5(x + 3). This equation can be further simplified to 3y - 9 = -5x - 15, or rearranged as: 5x + 3y = -6.