Question

For the system A +2B ⇌C, the equilibrium concentrations are (A) 0.06mole/litre (B) 0.12mole/litre (C) 0.216mole/litre. The Kₑᵩ for the reaction is

Answer 1

The equilibrium constant (Keq) for the reaction A + 2B ⇌ C, with the given equilibrium concentrations, is calculated to be 250.

Step-by-step explanation:

To determine the equilibrium constant (Keq) for the reaction A + 2B ⇌ C, given the equilibrium concentrations (A) 0.06mole/liter, (B) 0.12mole/liter, and (C) 0.216mole/liter, we use the equilibrium expression:

Keq = [C]/([A][B]2)

Substituting the provided equilibrium concentrations:

Keq = (0.216)/ (0.06*(0.12)2)

After calculating:

Keq = (0.216)/ (0.06*0.0144)

Keq = (0.216)/ (0.000864)

Keq = 250