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Find number assigned by the function f(x)=2x²+32x+2017 vertex.

User Spatak
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Final answer:

The vertex of the quadratic function f(x) = 2x² + 32x + 2017 is (-8, -336).

Step-by-step explanation:

The vertex form of a quadratic function is given by f(x) = a(x - h)² + k, where (h, k) represents the coordinates of the vertex.

In the given function f(x) = 2x² + 32x + 2017, we have a = 2, b = 32, and c = 2017.

To find the vertex, we can use the formula for the x-coordinate of the vertex, which is given by x = -b / (2a). Plugging in the values, we have x = -32 / (2 * 2) = -8. To find the y-coordinate of the vertex, we can substitute this value of x into the function: f(-8) = 2(-8)² + 32(-8) + 2017 = -336.

Therefore, the vertex of the function is (-8, -336).

User Taywee
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