Question

A teacher calculated the amount of sodium in the compound as 55 gm. The reference book said it was actually supposed to be 75 gm. What was the teacher's percent error?

a) 30.24%
b) 30.03%
c) 33.33%
d) 30.023%

Answer 1

The teacher's percent error in measuring the amount of sodium is found by subtracting the actual value from the measured value, dividing by the actual value, and then multiplying by 100%. The calculated error is 26.67%, but this does not match any of the provided options, indicating a possible mistake.

Step-by-step explanation:

The calculation of the teacher's percent error in the measurement of sodium in a compound involves comparing the measured value to the actual value and evaluating the discrepancy as a percentage. To find the percent error, the difference between the actual value and the measured value is divided by the actual value, and then multiplied by 100%.

1. Subtract the measured value (55 gm) from the actual value (75 gm) to find the error: 75 gm - 55 gm = 20 gm.
2. Divide the error by the actual value: 20 gm / 75 gm = 0.2667.
3. Convert the resultant to a percentage by multiplying by 100%: 0.2667 x 100% = 26.67%.

However, when we check the options provided (a) 30.24%, (b) 30.03%, (c) 33.33%, (d) 30.023%, none of them match the calculated result of 26.67%. It appears there might be a mistake either in the calculation or in the provided options. The correct answer is not listed.