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In a swimming class, four students swam 48 laps over a certain number of hours. Each student swom the number of hours showFL Student A: & hours Student B: 4 hours Student C: & hours Student D: & hours The number of laps swam by each student is proportional to the number of hours. Fill in the table with the amount of laps each student swam. Student Laps B D 1 T E Iv​

User Sadlil
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2 Answers

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Final answer:

The number of laps each student swam is proportional to the hours spent swimming. Assuming all students except for student B swam for 6 hours, and student B swam for 4 hours, the approximate laps swam per student were calculated by finding the rate of laps per hour and multiplying it by each student's swimming time.

Step-by-step explanation:

The given question asks us to determine how many laps each student swam in a swimming class, where the number of laps is proportional to the number of hours swum.

Since there is a typo in the hours swum by students C and D, and assuming they both swam 6 hours as written for both (similar to student A), we will use 6 hours for them as well.

To find the number of laps per hour, we divide the total laps (48) by the total number of hours swum by all students (assuming A, C, and D swam 6 hours each, and B swam 4 hours), which is 6+4+6+6=22 hours.

Now, we calculate the laps per hour:
48 laps ÷ 22 hours = 2.18 laps/hour (approximate value).

Each student's laps swam is then this rate multiplied by their swimming time:

  • Student A: 6 hours × 2.18 laps/hour = 13.08 laps
  • Student B: 4 hours × 2.18 laps/hour = 8.72 laps
  • Student C: 6 hours × 2.18 laps/hour = 13.08 laps
  • Student D: 6 hours × 2.18 laps/hour = 13.08 laps

As a result, the table will be filled with the approximate number of laps for each student based on the proportion of the hours they swam.

User Castrohenge
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5 votes

To find the number of laps each student swam, set up proportions using the given information of hours swam. Student C swam 72 laps and Student D swam 48 laps.

To fill in the table with the number of laps each student swam, we need to find the constant of proportionality. We can do this by using the information given. Student A swam 6 hours and Student B swam 4 hours, so the ratio of their laps is 6:4.

Similarly, the ratio of laps for Student C to Student B should be the same, and the ratio of laps for Student D to Student B should also be the same. So, we can set up the following proportions:

6/4 = x/48 (where x represents the number of laps Student C swam)

4/4 = y/48 (where y represents the number of laps Student D swam)

Solving these proportions, we find that x = 72 and y = 48. Therefore, Student C swam 72 laps and Student D swam 48 laps.

User Radiovisual
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