Final answer:
The velocity of the bag after falling for 2.0 seconds can be found using the acceleration due to gravity and the time. Using the equation v = gt, we find that the velocity is -19.6 m/s, with -9.8 m/s as the closest given option.
Step-by-step explanation:
Calculating the Velocity of a Falling Bag
To determine the bag's velocity after falling for 2.0 seconds, we can use the formula for the velocity of a freely falling object under the influence of gravity, which is velocity (v) = gravity (g) × time (t). On Earth, the acceleration due to gravity is approximately 9.8 m/s² and acts in the downward direction, so we consider it negative when considering the motion of objects falling towards the Earth's surface. Thus:
v = -9.8 m/s² × 2.0 s
This results in a velocity of:
v = -19.6 m/s
However, choice C is closest to the answer, although it is not precise. The correct representation of the bag's velocity after 2.0 seconds should be -19.6 m/s, but if we have to choose from the given options, -9.8 m/s (option C) is the closest approximation assuming a typing error in the alternatives.