Final answer:
For sanitary reasons, to achieve a chlorine concentration of 3.0 ppm in a pool containing 21,200 kg of water, 63.6 grams of chlorine is needed.
Step-by-step explanation:
To determine the required mass of chlorine to be added to a swimming pool to attain a maximum chlorine level of 3.0 ppm, we must first convert the volume of the pool to mass. Given that the typical 5,000-gallon swimming pool contains 21,200 kg of water, we can use the parts per million (ppm) concentration unit to make our calculations, since 1 ppm is equivalent to 1 milligram of solute per kilogram of solution (mg/kg).
Now, to find the required mass of chlorine for 3.0 ppm in a 21,200 kg swimming pool:
m_cl = concentration * mass_of_water
m_cl = 3.0 mg/kg * 21,200 kg
m_cl = 63,600 mg
Converting milligrams to grams, we get:
m_cl = 63.6 g
Therefore, to sanitize the pool water to a safe concentration of 3.0 ppm, 63.6 grams of chlorine must be added.