Question

Factorise the expression 8xy - 6y + 21x - 28x² by grouping.

A. 2x(4y - 7) - 3(2y - 7)
B. 4x(2y - 7) - 3(2y - 7)
C. (4y - 7)(2x - 3)
D. (2y - 7)(4x - 3)

Answer 1

To factorize the expression 8xy - 6y + 21x - 28x² by grouping, we can group the terms in pairs. Taking the common factor of 2y from the first two terms, we get 2y(4x - 3). Taking the common factor of 7 from the last two terms, we get 7(3x - 4x). Combining the two groups, we have the factored expression 2y(4x - 3) - 7(3x - 4x). Simplifying further, we obtain the final factored form of the expression as 2x(4y - 7) - 3(2y - 7), which corresponds to option A.

Step-by-step explanation:

To factorize the expression 8xy - 6y + 21x - 28x² by grouping, we can group the terms in pairs.

Taking the common factor of 2y from the first two terms, we get 2y(4x - 3).

Taking the common factor of 7 from the last two terms, we get 7(3x - 4x).

Combining the two groups, we have the factored expression 2y(4x - 3) - 7(3x - 4x).

Simplifying further, we obtain the final factored form of the expression as 2x(4y - 7) - 3(2y - 7), which corresponds to option A.