Question

The ages of three brothers are consecutive odd integers. The sum of all of their ages is 32 years more than the age of the youngest brother. What are the ages of the three brothers?

a. 7, 9, 11
b. 5, 7, 9
c. 11, 13, 15
d. 9, 11, 13

Answer 1

The ages of the three brothers are 13, 15, and 17 years.

Step-by-step explanation:

Let's represent the ages of the three brothers as x, x+2, and x+4, where x is the age of the youngest brother.

According to the given information, the sum of all their ages is 32 years more than the age of the youngest brother. So, we can write the equation:

x + (x+2) + (x+4) = x + 32

Simplifying the equation, we get:

3x + 6 = x + 32

2x = 26

x = 13

Therefore, the ages of the three brothers are 13, 15, and 17 years.