Final answer:
To find the energy absorbed when 6.5 grams of water evaporates, multiply the heat of vaporization of water (2,250 J/g) by the mass of water (6.5 g), resulting in 14,625 J. However, this result does not match the provided answer choices, suggesting an error in the question or references.
Step-by-step explanation:
The question asks us to calculate the amount of energy absorbed when 6.5 grams of water evaporates. To find the energy absorbed, we need to know the specific heat of vaporization of water, which is the amount of energy required to turn 1 gram of water into vapor at its boiling point without increasing temperature.
From the provided reference information, we know that it takes 2,250 J to evaporate each gram of water. To find the total energy absorbed for 6.5 grams, we simply multiply:
Energy absorbed = Heat of vaporization per gram × Mass of water
Energy absorbed = 2,250 J/g × 6.5 g
The arithmetic will yield the total energy absorbed:
Energy absorbed = 14,625 J
However, since this is not one of the provided options (A, B, C, D), it's possible there might be an error in either the information given in the problem, the reference provided, or the answer choices presented. In a real-world educational setting, this discrepancy would be raised with the educator for clarification.