Question

A car slows to a stop with an average acceleration of -1.5 m/s². How long does it take the car to slow down from 9.0 m/s to 0.0 m/s? (vf = vi + aΔt)

A. 2 seconds
B. 4 seconds
C. 6 seconds
D. 8 seconds

Answer 1

It takes 6 seconds for a car to slow down to a stop from 9.0 m/s with an average acceleration of -1.5 m/s².

Step-by-step explanation:

The question asks how long it takes for a car to slow to a stop from 9.0 m/s when it has an average acceleration of -1.5 m/s². Using the formula vf = vi + aΔt, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and Δt is the change in time, we can calculate the time taken for the car to slow down.

To find the time (Δt), rearrange the formula to solve for Δt: Δt = (vf - vi) / a. Plugging in the values, we get: Δt = (0.0 m/s - 9.0 m/s) / (-1.5 m/s²) = 6 seconds. Therefore, the correct answer is C. 6 seconds.