Question

A 5 kg block is pulled across the ground to the right by a tension force of 40 N with a frictional force of 8 N opposing the motion. What is the acceleration of the object?

Answer 1

You must use Fnet=ma

Ft-Ff=ma

40-8=5*a

a=6.4m/s^2

Answer 2

The Acceleration of the object = 6.4 m/s²

Mass of block (m) = 5 kg

Action force on block, (F₁) = 40 N

Frictional force opposing the motion (F₂) = 8 N

Acceleration of the object (a) = ?

⇒ Net force = Action force on block - Opposing friction force

⇒ F = F₁ - F₂

⇒ F = 40 - 8

⇒ F = 32 N

Net force of the block (F) = 32 N

Mass of block (m) = 5 kg

F is the Force in N.

m is the Mass in kg.

a is the Acceleration in m/s².

F = ma

⇛ a = F/m

⇛ a = 32/5

⇛ a = 6.4 m/s²