Question

√2(√45 + √80) = a√10. What is the value of 'a'?

A. a = √5

B. a = 5

C. a = √10

D. a = 10

Answer 1

The value of 'a' in the equation √2(√45 + √80) = a√10 is 7.

Step-by-step explanation:

To find the value of 'a' in the equation √2(√45 + √80) = a√10, we can simplify the expression inside the square root. √45 can be written as √9 √5, and √80 can be written as √16 √5. Applying the multiplication property of square roots, we have √2(√45 + √80) = √2(3√5 + 4√5) = √2 * 7√5 = 7√10. Therefore, the value of 'a' is 7.