Final answer:
To find out how many more tickets each class needs to sell so that both classes raise the same amount, we set up and solve equations based on the price of the tickets and the amount already raised. After solving, we find that each class needs to sell 40 more tickets for the total amounts raised to be the same. None of the options given in the question (A, B, C, D) are correct based on our calculation.
Step-by-step explanation:
The student is asking how many tickets each of two eighth-grade classes must sell for their school fundraiser so that the total amount raised by each class is the same. One class sells tickets at $4.50 each and has already raised $350, while the other sells them for $3.25 each and has raised $400. We can solve this by setting up two equations that represent the total amount of money raised if both classes sell x additional tickets.
For the first class: 4.50x + 350 = Total amount raised
For the second class: 3.25x + 400 = Total amount raised
Because we want the total amounts raised to be the same, we can set the two equations equal to each other:
4.50x + 350 = 3.25x + 400
Solving for x, we subtract 3.25x from both sides:
1.25x + 350 = 400
Then, subtract 350 from both sides:
1.25x = 50
Finally, divide both sides by 1.25:
x = 40
Hence, the first class must sell 40 more tickets and the second class must also sell 40 more tickets for the total amount raised by each class to be the same. The options provided (A, B, C, D) do not match our solution, which suggests that the amount each class needs to sell for the total to be the same is not provided in the choices listed.