Final answer:
The normal force acting on the suitcase is approximately 166 N, and the acceleration of the suitcase is 0.8 m/s², none of which match the provided options A, B, C, or D.
Step-by-step explanation:
To determine the normal force acting on the suitcase, we must consider the components of the pull force, the weight of the suitcase, and the effect of the angle at which the force is applied. The vertical component of the pull force, which counteracts the weight, is calculated using the sine of the angle (35 N × sin(60°)). The weight of the suitcase is its mass times the acceleration due to gravity (20 kg × 9.81 m/s²). The normal force is the difference between the weight and the vertical component of the pull force.
To find the acceleration of the suitcase, we use Newton's second law (F=ma). The total force in the horizontal direction is the horizontal component of the pull force minus the force of friction (35 N × cos(60°) - 1.5 N), and then this force is divided by the mass of the suitcase.
Calculations:
- Weight of the suitcase: 20 kg × 9.81 m/s² = 196.2 N
- Vertical component of the pull force: 35 N × sin(60°) = 30.31 N
- Normal force: 196.2 N - 30.31 N = 165.89 N (approximately 166 N)
- Horizontal component of the pull force: 35 N × cos(60°) = 17.5 N
- Total horizontal force: 17.5 N - 1.5 N = 16 N
- Acceleration: 16 N / 20 kg = 0.8 m/s²
Therefore, the normal force is approximately 166 N, and the acceleration is 0.8 m/s². None of the answer choices A, B, C, or D match these calculated values.