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What is the expression for the amount of a certain radioactive substance as a function of time (t) with a half-life of 14 days and an initial amount of 2.5 grams? When will there be less than 1 gram remaining?

A) A(t) = 2.5 * (1/2)^(t/14)
B) A(t) = 2.5 - t/14
C) A(t) = 2.5 * t/14
D) A(t) = 2.5 + t/14

1 Answer

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Final answer:

The expression for the amount of a certain radioactive substance as a function of time with a half-life of 14 days and an initial amount of 2.5 grams is A(t) = 2.5 * (1/2)^(t/14). To find when there will be less than 1 gram remaining, we solve the equation 1 = 2.5 * (1/2)^(t/14) and approximate t to be approximately 16.22 days.

Step-by-step explanation:

The expression for the amount of a certain radioactive substance as a function of time is given by option A) A(t) = 2.5 * (1/2)^(t/14). This equation represents exponential decay, where the initial amount is multiplied by the decay factor (1/2) raised to the power of the elapsed time divided by the half-life.

To determine when there will be less than 1 gram remaining, we can set the expression equal to 1 and solve for t:

1 = 2.5 * (1/2)^(t/14)

By taking the logarithm of both sides, we can isolate the exponent t/14:

t/14 = log(base 1/2)(1/2.5)

Using the logarithmic property that log(base b)(b^x) = x, we get:

t/14 = log(base 1/2)(1/2.5) = -log(base 2)(2.5)

Multiplying both sides by 14 and dividing by log(base 2)(2.5), we find:

t = -14 * log(base 2)(2.5)

Using a calculator, we can approximate the value of t to be approximately 16.22 days.

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