Final answer:
The volume of seawater displaced by the ship is calculated using Archimedes' principle and the given density of seawater. With the ship's mass at 1,200,000 kg and seawater's density at 1.03 kg/L (or 1030 kg/m³), the displaced volume is found to be 1165.05 m³.
Step-by-step explanation:
To calculate the volume of seawater displaced by the ship, we use Archimedes' principle, which states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. Since the ship is floating, the weight of the displaced seawater must equal the total weight of the ship and its cargo.The density of seawater is given as 1.03 kg/L (or 1030 kg/m³ since 1 L = 0.001 m³). The mass of the ship and cargo is 1,200,000 kg. Using the formula for density (ρ = m/V, where ρ is density, m is mass, and V is volume), we can rearrange to find volume (V = m/ρ).Thus, the volume of seawater displaced is V = 1,200,000 kg / 1030 kg/m³.
Calculating this we get:
V = 1165.05 m³ (rounded to two decimal places).