Question

At a pressure of 800.00 kPa, a gas occupies 225.0 mL. What is the final pressure in atm when the gas later occupies 1.2 L?

Answer 1

To determine the final pressure of a gas when the volume increases, Boyle's Law can be used after converting the initial pressure from kPa to atm and the initial volume from mL to L. Calculating with the provided values gives a final pressure of approximately 1.48 atm when the gas occupies 1.2 L.

Step-by-step explanation:

To find the final pressure in atm when the gas later occupies 1.2 L, starting from a pressure of 800.00 kPa and a volume of 225.0 mL, we can use Boyle's Law, which states that for a given mass of enclosed gas with constant temperature, the pressure is inversely proportional to the volume (P1V1 = P2V2).

First, we convert the initial pressure from kPa to atm (1 atm = 101.325 kPa):

Initial pressure in atm = 800.00 kPa / 101.325 kPa/atm = 7.89 atm (approximately)

Next, we convert the initial volume from mL to L:

Initial volume in L = 225.0 mL / 1000 mL/L = 0.225 L

Now we apply Boyle's Law:

7.89 atm * 0.225 L = P2 * 1.2 L

P2 = (7.89 atm * 0.225 L) / 1.2 L

P2 = 1.48 atm (approximately)

Therefore, the final pressure of the gas when it occupies 1.2 L is roughly 1.48 atm.