Question

Consider function h.

h(x) =
2x² + 3x + 10, 0 < x < 4
2x + 5, x ≥ 4
What are the values of the function when x = 0 and when x = 4?

Answer 1

The value of the function when x = 0 is 10 and when x = 4 is 173.

Step-by-step explanation:

The given function is:

h(x) = 2x² + 3x + 10, 0 < x < 4

h(x) = 42x + 5, x ≥ 4

To find the values of the function when x = 0 and x = 4, we substitute the values of x into the given function:

When x = 0:

h(0) = 2(0)² + 3(0) + 10 = 10

When x = 4:

h(4) = 42(4) + 5 = 173

Therefore, the value of the function when x = 0 is 10 and when x = 4 is 173.