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What is the equation of the line that is parallel to the line y = -13x + 5 and passes through the point (3,4)?

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Final answer:

The equation of the line parallel to y = -13x + 5 and passing through the point (3,4) is y = -13x + 43.

Step-by-step explanation:

The equation of the line parallel to y = -13x + 5 and passing through the point (3,4) can be found by observing that parallel lines have the same slope. Since the given line has a slope of -13, the parallel line will also have a slope of -13. Using the point-slope form of a linear equation, y - y1 = m(x - x1), we can substitute the values of (x1, y1) = (3,4) and m = -13 to find the equation of the line:

y - 4 = -13(x - 3)

Expanding the equation gives: y = -13x + 43

User Bas Verlaat
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