Question

A cannon launches a 3.0 kg pumpkin with 110 J of kinetic energy.What is the pumpkin’s speed?

a) 2.52 m/s
b) 5.37 m/s
c) 8.20 m/s
d) 10.91 m/s

Answer 1

To find the pumpkin's speed when launched with 110 J of kinetic energy, use the kinetic energy formula to get a velocity of 5.37 m/s. The correct answer is choice b) 5.37 m/s.

Step-by-step explanation:

The question asks for the speed of a 3.0 kg pumpkin when it is launched with 110 J of kinetic energy. To find the speed, we can use the kinetic energy formula KE = 0.5 × m × v^2, where KE is kinetic energy, m is mass, and v is velocity.

First, we rearrange the formula to solve for velocity: v = √(2×KE/m). Then we plug in the given values, v = √(2×110 J / 3.0 kg), which calculates to a velocity of 5.37 m/s. Therefore, the correct answer is b) 5.37 m/s.

Answer 2

KE = 0.5 * m * v^2
110J = 0.5 * 3kg * v^2
v^2 = 73.33
v = 8.56 m/s