Question

The temperature of 50g of water was raised to 50°C by the addition of 1000J of heat energy. What was the initial temperature of the water?

Answer 1

To find the initial temperature, we can use the equation Q = mcΔT and rearrange it to solve for the initial temperature. Plugging in the given values, we find that the initial temperature is approximately 45.22°C.

Step-by-step explanation:

To determine the initial temperature of the water, we need to use the equation Q = mcΔT, where Q represents the heat energy, m represents the mass of the water, c represents the specific heat capacity of water, and ΔT represents the change in temperature. given that 1000J of heat energy is added to 50g of water and the final temperature is 50°C, we can rearrange the equation to solve for the initial temperature. The specific heat capacity of water is approximately 4.18 J/g°C. Plugging in the values, we have:

1000J = (50g)(4.18 J/g°C)(50°C - initial temperature)

Simplifying this equation, we find:

initial temperature = 50°C - (1000J / (50g)(4.18 J/g°C))

Calculating this expression, we get:

initial temperature ≈ 50°C - 4.78°C ≈ 45.22°C