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An arrow is launched straight up from the ground with an initial velocity of 23.4 m/s.

1. How long until it reaches its highest point?
2. How high does it travel?

1 Answer

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Final answer:

The question is about calculating the time and height of an arrow shot straight up in physics, specifically using kinematics and projectile motion equations.

Step-by-step explanation:

The subject of the given question is physics, specifically dealing with projectile motion and kinematics. To answer how long it will take the arrow to reach its highest point, you need to consider the vertical component of the initial velocity and the acceleration due to gravity.

The formula to use is v = u + at, where v is the final velocity (0 m/s at the highest point), u is the initial velocity (23.4 m/s), a is the acceleration (-9.8 m/s2, negative because it's opposite to the initial velocity), and t is the time. To find the height the arrow travels, the formula s = ut + 0.5at2 can be used, where s is the height.

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