116k views
1 vote
Write an equation and solve algebraically: Two consecutive integers have the property that when the smaller number is added to four times the larger number, the result is 29. Find the two consecutive integers.​ A) 4 and 5

B) 5 and 6
C) 6 and 7
D) 7 and 8
E) 8 and 9

User M I P
by
8.3k points

1 Answer

3 votes

Final answer:

To solve the problem, we assume that the smaller consecutive integer is x and the larger consecutive integer is x+1. We then set up an equation and solve for x, resulting in the smaller integer being 5 and the larger integer being 6.

Step-by-step explanation:

To solve this problem, let's assume that the smaller consecutive integer is x and the larger consecutive integer is x+1. According to the given information, when the smaller number is added to four times the larger number, the result is 29.

So, we can write the equation as:

x + 4(x+1) = 29

Simplifying the equation:

x + 4x + 4 = 29

Combining like terms:

5x + 4 = 29

Subtracting 4 from both sides:

5x = 25

Dividing both sides by 5:

x = 5

Therefore, the smaller consecutive integer is 5 and the larger consecutive integer is x+1 = 5+1 = 6.

So, the correct answer is B) 5 and 6.

User JMcClure
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories