To find the equation of the line passing through the points (3, -8) and (6, -4), you can use the slope-intercept form of a linear equation, which is given by:
y = mx + b
where:
- m is the slope of the line,
- b is the y-intercept (the y-coordinate where the line crosses the y-axis).
First, calculate the slope (m) using the formula:
m = (y_2 - y_1) / (x_2 - x_1)
Using the points (3, -8) and (6, -4):
m = (-4) - (-8) / 6 - 3
m = 4/3
Now that you have the slope (m), you can use one of the points to find the y-intercept (b). Let's use the point (3, -8):
y = mx + b
-8 = 4/3(3) + b
Now, solve for b:
-8 = 4 + b
b = -12
Now that you have both the slope (m) and the y-intercept (b), you can write the equation of the line:
y = 4/3x - 12
So, the equation of the line passing through the points (3, -8) and (6, -4) is y = 4/3x - 12.
hope this helps :)