Question

A hunter shoots a 0.003 kg bullet at a deer 50 meters away. If the bullet accelerates at 2.6 x 10⁵ m/sec² and the mass of the gun is 2.5 kg, how many newtons of force is exerted on the bullet?

Answer 1

The force exerted on the bullet is calculated using Newton's second law of motion, resulting in a force of 780 newtons.

Step-by-step explanation:

The subject of this question is Physics, more specifically it involves concepts from Newton's second law of motion and kinematics. To calculate the force exerted on a bullet by a gun, we use Newton's second law which states that the force exerted on an object is equal to the mass of the object times its acceleration (F = m × a).

In this scenario, the mass of the bullet is given as 0.003 kg, and it accelerates at 2.6 × 10⁵ m/s². Applying the formula, the force exerted on the bullet is F = 0.003 kg × 2.6 × 10⁵ m/s² = 780 N.