Question

A number cube is rolled. What is the probability of not rolling a 2 or 3?

A) 5/6
B) 2/3
C) 1/3
D) 1/6

Answer 1

The probability of not rolling a 2 or 3 when a fair six-sided die is rolled is 2/3, as there are 4 favorable outcomes out of 6 possible outcomes which simplifies to 2/3.

Step-by-step explanation:

The question asks us to find the probability of not rolling a 2 or 3 when a number cube (a fair six-sided die) is rolled. There are four favorable outcomes as there are six possible outcomes in total (1, 4, 5, and 6) and two outcomes that are not favorable (2 and 3). The probability of an event is calculated by the number of favorable outcomes divided by the total number of possible outcomes. Therefore, the probability of not rolling a 2 or 3 is:

• Number of favorable outcomes: 4 (1, 4, 5, 6)
• Total possible outcomes: 6 ({1, 2, 3, 4, 5, 6})
• Probability = Number of favorable outcomes / Total possible outcomes = 4/6

This simplifies to 2/3 because 4 and 6 both divide by 2. So the probability of not rolling a 2 or 3 is 2/3, which is option B).