Question

A cannon shoots a 30.95 kg ball at a sailing ship, and when it hits the wall of the vessel, it applies 1,895.56 Newtons of force. How much was it decelerated?

Answer 1

The cannonball decelerated at 61.22 meters per second squared when it hit the ship's wall, calculated by applying Newton's second law of motion and dividing the force by the mass of the cannonball.

Step-by-step explanation:

To calculate the deceleration experienced by the 30.95 kg cannonball when it applies a force of 1,895.56 Newtons upon hitting the wall of the vessel, we use Newton's second law of motion, F = ma, where F is the force applied, m is the mass of the object, and a is the acceleration (or deceleration in this case).

We need to rearrange the formula to solve for a: a = F / m. Plugging in the values given, the deceleration a is equal to 1,895.56 N divided by 30.95 kg, which gives us the deceleration experienced by the cannonball.

Performing the calculation:
a = 1,895.56 N / 30.95 kg = 61.22 m/s²

The cannonball decelerated at 61.22 meters per second squared when it hit the ship's wall.