Question

if the total pressure of a mixture of gases was 760 mm hg and its composition is 20% oxygen, 0.04% carbon dioxide, 75% nitrogen, and 5% water vapor, then the partial pressure of oxygen would be a. 740 mm hg. b. 152 mm hg. c. 20 mm hg. d. 148 mm hg. e. 200 mm hg.

Answer 1

The partial pressure of oxygen in a gas mixture with a total pressure of 760 mm Hg and an oxygen composition of 20% is 152 mm Hg. Option b is the answer.

Step-by-step explanation:

To calculate the partial pressure of oxygen in a gas mixture with a total pressure of 760 mm Hg, you can use the formula for partial pressures:

P = (Patm) X (percent content in mixture).

The composition of the gas mixture given is 20% oxygen, so to find the partial pressure of oxygen, multiply the total pressure by the percent of oxygen in decimal form:

PO2 = (760 mm Hg) X (0.20) = 152 mm Hg.

Therefore, the partial pressure of oxygen in the gas mixture is 152 mm Hg, which corresponds to option (b).