Question

in the presence of quanta, a disgruntled student throws a bottle toward the pillar in the classroom. (4 points) a. what is the height at which the bottle makes contact with the pillar? b. what is the speed of the bottle at the moment of impact with the pillar?

Answer 1

In presence of quanta H =1.85m and v=6.34m/s. Therefore, the correct answer is H =1.85m and v=6.34m/s is correct .

we can use the following steps:

Calculate the initial velocity of the bottle. We know that the bottle is thrown at a speed of 15 m/s and at an angle of 25 degrees. We can use the following equation to calculate the initial velocity in the vertical direction:

v_y = v_i * sin(theta)

where:

v_i is the initial velocity

theta is the angle of projection

v_y = 15 m/s * sin(25 degrees)

v_y = 6.34 m/s

Calculate the time it takes for the bottle to reach the pillar. We can use the following equation to calculate the time of flight:

t = 2 * v_y / g

where:

g is the acceleration due to gravity (9.81 m/s^2)

t = 2 * 6.34 m/s / 9.81 m/s^2

t = 1.27 s

Calculate the height at which the bottle makes contact with the pillar. We can use the following equation to calculate the vertical displacement:

h = v_y * t - 1/2 * g * t^2

h = 6.34 m/s * 1.27 s - 1/2 * 9.81 m/s^2 * (1.27 s)^2

h = 1.85 m .