The average upward force exerted by the water on the diver is 572.97 N.
Initial velocity (v_initial): 0 m/s (starts from rest)
Final velocity (v_final): 0 m/s (stopped by water)
Acceleration due to gravity (g): 9.81 m/s^2
Height (h): 10.0 m
Mass of the diver (m): 58.3 kg
Time taken to stop (t): 1.90 s
Work done by the water:
W = F * h
Change in kinetic energy:
KE = (1/2) * m * (v_final^2 - v_initial^2)
Setting work equal to change in energy:
F * h = (1/2) * m * (v_final^2 - v_initial^2)
Solving for the upward force (F):
F = [(1/2) * m * (v_final^2 - v_initial^2)] / h
Calculating the final velocity (v_final):
v_final = v_initial + g * t
v_final = 0 + 9.81 * 1.90 = 18.66 m/s
Substituting values to find F:
F = [(1/2) * 58.3 * (18.66^2 - 0^2)] / 10.0
F = 572.97 N
Therefore, the correct upward force exerted by the water on the diver is 572.97 N.