Question

you have a single 9 v battery and two lightbulbs. if one lightbulb has a resistance of 20 ohms and the other has a resistance of 40 ohms, which would have a bigger current through it if you hooked it up to the battery?

Answer 1

The 20-ohm lightbulb will have a bigger current running through it when connected to a 9V battery, as per Ohm's law, which indicates a lower resistance results in a higher current when voltage is constant.

Step-by-step explanation:

Between the lightbulb with 20 ohms resistance and the one with 40 ohms resistance, the one with 20 ohms will have a bigger current running through it when connected to a 9V battery.

According to Ohm's law, which states that current (I) is equal to the voltage (V) divided by resistance (R), a lower resistance will result in a higher current if the voltage is constant.

Thus, for the 20-ohm bulb, I = V/R = 9V/20Ω = 0.45A, and for the 40-ohm bulb, I = 9V/40Ω = 0.225A.

Therefore, the 20-ohm lightbulb will have a current of 0.45 amperes, which is greater than the 0.225 amperes flowing through the 40-ohm lightbulb.