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two balloons have the same size (6.00 l). the first balloon is filled with 2.0 moles of helium. the second balloon is filled with nitrogen gas. how many grams of nitrogen gas are inside of the second balloon? assume the temperature and pressure of the gases are constant.

User SiH
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Final answer:

The second balloon, under the same conditions as the helium-filled balloon, contains 2.0 moles of nitrogen gas. With a molar mass of 28.02 grams per mole of nitrogen, the balloon holds 56.04 grams of nitrogen gas.

Step-by-step explanation:

To determine how many grams of nitrogen gas are inside the second balloon we can use the ideal gas law, which is PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature. Since the conditions are constant and given that the volume is the same for both helium and nitrogen, the number of moles of gas should be the same as well. Hence, the second balloon also contains 2.0 moles of nitrogen gas.

The molar mass of nitrogen gas (N2) is 28.02 grams per mole. We can then calculate the mass of nitrogen gas in the second balloon by multiplying the number of moles by the molar mass of nitrogen:

Mass = number of moles × molar mass of nitrogen

Mass = 2.0 moles × 28.02 g/mole

Mass = 56.04 grams

Therefore, the second balloon contains 56.04 grams of nitrogen gas.

User Markus Andreas
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