Question

What are the solutions of this quadratic equation?

2x2 + 16x − 8 = 0

Answer 1

`x= -4` +
`2√(5)` and
`x= -4 -2√(5)`

Explanation:

`ax^(2)` +
`bx` -
`c = 0`

For this equation:
`a = 2, b = 16, c = -8`

`2x^(2)` +
`16x` -
`8 = 0`

Step 1: Use quadratic formula with
`a=2, b=16, c=-8`

`x=\frac{-b + - \sqrt{b^(2)-4ac } }{2a}`

`x=\frac{-(16) + - \sqrt{16^(2)-4(2)(-8) } }{2(-2)}`

`x=(-16+- √(320) )/(4)`

`x= -4` +
`2√(5)` and
`x= -4 -2√(5)`

Hope this helps! :)