Final answer:
The probability that Banfield is the first presenter and Shepherd is the last presenter is 0.5.
Step-by-step explanation:
To find the probability that Banfield is the first presenter and Shepherd is the last presenter, we need to consider the number of possible orders in which the presentations can be arranged.
Since there are 2 presenters, there are 2! = 2 factorial = 2 ways to arrange them.
However, since we are specifically looking for the case where Banfield is first and Shepherd is last, we only need to consider 1 arrangement.
Therefore, the probability is 1/2 = 0.5.