The net impulse delivered by the force is 36 N s.
The net impulse delivered by a force is equal to the change in momentum of the object. This can be expressed mathematically as follows:
J = Δp = mv_f - mv_i
where:
J is the net impulse (Ns)
m is the mass of the object (kg)
v_f is the final velocity of the object (m/s)
v_i is the initial velocity of the object (m/s)
In this case, the object starts from rest, so v_i = 0. We need to find the final velocity, v_f, and then we can calculate the net impulse.
To find v_f, we can use the following equation:
v_f = v_i + at
where:
a is the acceleration of the object (m/s^2)
t is the time interval (s)
We can find the acceleration by using the following equation:
a = F/m
where:
F is the net force applied to the object (N)
The net force applied to the object is given by the graph. We can see that the force increases linearly from 0 N to 12 N over a time interval of 2 s. This means that the average acceleration of the object is:
a = (12 N - 0 N) / 2 s = 6 m/s^2
Now that we know the acceleration, we can find the final velocity:
v_f = v_i + at = 0 m/s + 6 m/s^2 * 2 s = 12 m/s
Finally, we can calculate the net impulse:
J = Δp = mv_f - mv_i = 3 kg * 12 m/s - 3 kg * 0 m/s = 36 Ns
Question
An object of mass 3 kg starts from rest and moves along the x-axis. A net horizontal force is applied to the object in +x direction. The force time relations presented by the graph. What is the net impulse delivered by this force?