Question

beth banfield and boyd shepherd are among representatives making presentations at the annual sales meeting. the presentations are randomly ordered. find the probability that is the first presented and is the last presented.

Answer 1

The probability of Beth being the first presenter and Boyd being the last presenter is 0.5.

Step-by-step explanation:

To find the probability that Beth Banfield is the first presenter and Boyd Shepherd is the last presenter at the annual sales meeting, we need to consider the number of possible orders in which the presentations can be arranged.
Since the presentations are randomly ordered, there are n! (n factorial) possible orders, where n is the total number of presenters. In this case, n = 2.

So, the probability that Beth is the first presenter and Boyd is the last presenter is:

P(Beth is first and Boyd is last) = 1 / n! = 1 / 2! = 1 / 2 = 0.5