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let's say are a playing a game in which you must flip a (fair) coin and land on heads 3 times in a row. what is the probability you will win in 6 total flips or fewer?

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Final answer:

The probability of winning the game in 6 total flips or fewer is 1/8 or 12.5%.

Step-by-step explanation:

To find the probability of winning the game in 6 total flips or fewer, we need to calculate the probability of achieving 3 consecutive heads within those 6 flips.

Since the coin is fair, the probability of getting heads on a single flip is 1/2. To calculate the probability of getting 3 consecutive heads, we multiply this probability by itself three times:

P(3 heads in a row) = (1/2) x (1/2) x (1/2) = 1/8

Therefore, the probability of winning the game in 6 total flips or fewer is 1/8, or 12.5%.

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