Question

in a recent poll, 210 people were asked if they liked dogs, and 81% said they did. find the margin of error for this poll, at the 95% confidence level. give your answer to four decimal places if possible.

Answer 1

To find the margin of error for a poll, use the formula: ME = z * sqrt((p * (1-p))/n), where z is the z-score corresponding to the desired confidence level, p is the proportion of people who said they liked dogs, and n is the sample size. Substituting the given values, we find that the margin of error is approximately 0.0591.

Step-by-step explanation:

To find the margin of error for a poll, we can use the formula:

ME = z * sqrt((p * (1-p))/n)

Where:

• ME is the margin of error
• z is the z-score corresponding to the desired confidence level
• p is the proportion of people who said they liked dogs
• n is the sample size

In this case, the proportion of people who said they liked dogs is 81% (or 0.81), the sample size is 210, and we want to find the margin of error at the 95% confidence level. The z-score corresponding to a 95% confidence level is approximately 1.96.

Substituting these values into the formula, we get:

ME = 1.96 * sqrt((0.81 * (1-0.81))/210) = 0.0591

So the margin of error for this poll, at the 95% confidence level, is approximately 0.0591.