The distance between the minima and the central maximum is 43.2032 nm.
Given a setup with slit width of 569 micron/micrometer and a minima of order 8 with wavelength of 5904 nm, what is the distance (in nm) between the minima and the central maximum if the screen distance is 576 nm. Round to 4 decimals.
We can solve this problem by using the formula for the distance between minima and the central maximum:
d = mλD / a
where:
d is the distance between the minima and the central maximum
m is the order of the minima
λ is the wavelength of light
D is the distance from the slit to the screen
a is the width of the slit
We are given that m = 8, λ = 5904 nm, D = 576 nm, and a = 569 µm. We need to find d in nm.
First, let's convert the width of the slit from µm to nm:
a = 569 µm * 1000 nm/µm = 569000 nm
Now, we can plug all the values into the formula:
d = 8 * 5904 nm * 576 nm / 569000 nm = 43.2032 nm
Therefore, the distance between the minima and the central maximum is 43.2032 nm, rounded to 4 decimal places.
Question:-
Given a setup with slit width of 569 micron/micrometer and a minima of order 8 with wavelength of 5904 nm, what is the distance (in nm) between the minima and the central maximum if the screen distance is 576 nm. Round to 4 decimals.