The equation of 0,0 order pairs straight lines is y = mx, where m is the slope. the equation of a straight line that passes through the origin on a Cartesian plane, which simplifies to y = mx, where m is the slope obtained from the angle of inclination using m = tan(θ).
The question appears to be asking about the equation of a straight line that passes through the origin (0,0), which is often referred to as the 'origin' in mathematics. Specifically, it seems to be asking for the equation of a line where both the 'launch point' and 'impact point' are at position zero on a flat horizontal surface, an idea that might come from physics, particularly projectile motion.
In mathematics, the equation of a straight line in the slope-intercept form is given by y = mx + b, where m is the slope of the line and b is the y-intercept. For lines passing through the origin, the y-intercept is zero, hence the equation simplifies to y = mx. If we know the angle of inclination θ, we can find the slope m using m = tan(θ). This is because the slope is equal to the rise over run, which corresponds to the trigonometric functions for a right triangle formed by the line and the x-axis.
The graph of a linear equation depicts these lines on a Cartesian coordinate system, which is composed of two perpendicular lines called axes. This system is used to plot points and lines on a two-dimensional plane and can be extended to three dimensions with the addition of a z-axis.
For example, the equation y = 2x represents a straight line with a slope of 2 that passes through the origin (0,0). Similarly, the equation y = -3x represents a straight line with a slope of -3 that also passes through the origin.
Therefore, the equation of 0,0 order pairs straight lines can be written as y = mx, where m is the slope.