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23 votes
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the

time after launch, x in seconds, by the given equation. Using this equation, find the
maximum height reached by the rocket, to the nearest tenth of a foot.
y = -16x2 + 160x + 51

User RFV
by
7.8k points

1 Answer

10 votes

Answer:

451

Explanation:

on a calculator go to y= and type the equation in and then go to the table.

User Davis
by
8.4k points
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