Final answer:
AlCl3 has more polar bonds than AlBr3 due to the greater electronegativity difference between aluminum and chlorine compared to that between aluminum and bromine.
Step-by-step explanation:
To determine which compound between AlCl3 and AlBr3 has more polar bonds, we look at the electronegativity difference between the aluminum (Al) and the halogens (Cl and Br).
Chlorine (Cl) has an electronegativity of 3.16, while bromine (Br) has an electronegativity of 2.96.
Since aluminum's electronegativity is 1.61, the electronegativity difference for Al-Cl is 1.55 and for Al-Br is 1.35.
A larger electronegativity difference indicates a more polar bond, making AlCl3 the compound with the more polar bonds.
Electronegativity difference is a key factor in determining the polarity of a bond, with a larger difference leading to a more polar bond.